imported>Unknown at 05:23, 7 February 2021

2021-02-07T05:23:38Z

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== LightMoreLight/허아영 ==
{| class="wikitable"
|-
| 2006-02-11 Time Limit Exceeded 10.051 440
|}

ㅋㅋ for 때문에 시간이 걸리네.ㅠ
ㅁㅣ완성 ~ ㅋㅋ

수식을 만들어야겠다 ㅋㅂ

# before..
As problem,
equally I do.

# different idea..
simply,, I thinked..
If the Number of n's measure is an odd number, an answer is "No"
else if the Number of n's measure is an even number, an answer is "Yes".

How do I code this contents??

I learned how to solve the Number of n's measure.. at a middle school.
6 = 2^1 * 3^1
(index+1)s multiplication -> 2 * 2 = 4
6's measure are 1, 2, 3, 6
total 4!!!

== 코드 ==
#include <iostream>
using namespace std;

int process(int n)
{
int i = 0, j = 0;
int state = 0;

for(i = 1; i <= n; i++) // n 번 왕복,
{
if(n % i == 0)
state = ~state;
}
return state; // 마지막
}

int main()
{
int n;
int result = 0;
while(1)
{
cin >> n;
if(n == 0)
break;
result = process(n);
if(result == 0)
cout << "no" << endl;
else
cout << "yes" << endl;
}
return 0;
}

LightMoreLight/허아영 - Revision history

imported>Unknown at 05:23, 7 February 2021