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	<title>XOR삼각형 - Revision history</title>
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	<updated>2026-05-15T00:15:31Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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	<entry>
		<id>https://mediawiki.zeropage.org/index.php?title=XOR%EC%82%BC%EA%B0%81%ED%98%95&amp;diff=40342&amp;oldid=prev</id>
		<title>imported&gt;Unknown at 05:28, 7 February 2021</title>
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		<updated>2021-02-07T05:28:27Z</updated>

		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;파스칼의 삼각형에서 덧셈의 기본 연산을 XOR로 치환한 XOR삼각형 만들기&lt;br /&gt;
----&lt;br /&gt;
 [[파스칼삼각형]]과 기본적인 틀은 같습니다만&lt;br /&gt;
 머리위의 두 숫자를 더하는 것이 아닌 XOR연산을 합니다.&lt;br /&gt;
 XOR연산은 두개의 숫자가 같으면 0, 다르면 1 입니다. (DeleteMe XOR 연산의 보다 정확한 정의는 같으면 0, 다르면 1이 아니고 1의 갯수가 홀수일때 1, 짝수일 때 0 입니다)&lt;br /&gt;
(&lt;br /&gt;
예제&lt;br /&gt;
         1&lt;br /&gt;
       1 1&lt;br /&gt;
      1 0 1&lt;br /&gt;
     1 1 1 1&lt;br /&gt;
    1 0 0 0 1&lt;br /&gt;
   1 1 0 0 1 1&lt;br /&gt;
  1 0 1 0 1 0 1&lt;br /&gt;
 1 1 1 1 1 1 1 1&lt;br /&gt;
&lt;br /&gt;
== 진행 ==&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|-&lt;br /&gt;
| 도전자&lt;br /&gt;
| 총개발시간&lt;br /&gt;
| 소스라인수(&amp;#039;&amp;#039;&amp;#039;주석제외&amp;#039;&amp;#039;&amp;#039;)&lt;br /&gt;
| 사용언어&lt;br /&gt;
| Source&lt;br /&gt;
|-&lt;br /&gt;
| .&lt;br /&gt;
| .&lt;br /&gt;
| .&lt;br /&gt;
| .&lt;br /&gt;
| [[XOR삼각형/곽세환]]&lt;br /&gt;
|-&lt;br /&gt;
| .&lt;br /&gt;
| .&lt;br /&gt;
| .&lt;br /&gt;
| .&lt;br /&gt;
| [[XOR삼각형/aekae]]&lt;br /&gt;
|-&lt;br /&gt;
| 임인택&lt;br /&gt;
| 10분&lt;br /&gt;
| 17&lt;br /&gt;
| Python&lt;br /&gt;
| [[XOR삼각형/임인택]]&lt;br /&gt;
|-&lt;br /&gt;
| 허아영&lt;br /&gt;
| 몇십분&lt;br /&gt;
| .&lt;br /&gt;
| C&lt;br /&gt;
| [[XOR삼각형/허아영]]&lt;br /&gt;
|-&lt;br /&gt;
| 임다찬&lt;br /&gt;
| .&lt;br /&gt;
| .&lt;br /&gt;
| C&lt;br /&gt;
| [[XOR삼각형/임다찬]]&lt;br /&gt;
|-&lt;br /&gt;
| 이태양&lt;br /&gt;
| .&lt;br /&gt;
| .&lt;br /&gt;
| C&lt;br /&gt;
| [[XOR삼각형/이태양]]&lt;br /&gt;
|}&lt;br /&gt;
----&lt;br /&gt;
[[문제분류]]&lt;br /&gt;
&lt;/div&gt;</summary>
		<author><name>imported&gt;Unknown</name></author>
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