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다른 언어라면 이렇게 쉽게 안되었을 문제인데, 역시 Python입니다 ^ 오 ^ | 다른 언어라면 이렇게 쉽게 안되었을 문제인데, 역시 Python입니다 ^ 오 ^ | ||
= EightQueenProblem = | |||
# Start Time : 2014. 03. 16. 1:08 | # Start Time : 2014. 03. 16. 1:08 | ||
# End Time : 2014. 03. 16. 1:24 | # End Time : 2014. 03. 16. 1:24 | ||
| Line 19: | Line 19: | ||
=EightQueenProblem2= | |||
from itertools import permutations | from itertools import permutations | ||
n = 8 | n = 8 | ||
Revision as of 16:43, 15 March 2014
다른 언어라면 이렇게 쉽게 안되었을 문제인데, 역시 Python입니다 ^ 오 ^
EightQueenProblem
- Start Time : 2014. 03. 16. 1:08
- End Time : 2014. 03. 16. 1:24
from itertools import permutations
n = 8
cols = range(n)
for vec in permutations(cols):
if n == len(set(vec[i]+i for i in cols)) == len(set(vec[i]-i for i in cols)):
for i in cols:
for j in cols:
if vec[i] == j: print ('Q'),
else: print '#',
print
print
break
EightQueenProblem2
from itertools import permutations
n = 8
cols = range(n)
for vec in permutations(cols):
if n == len(set(vec[i]+i for i in cols)) == len(set(vec[i]-i for i in cols)):
print vec