More actions
No edit summary |
(Repair batch-0006 pages from live compare) |
||
| (2 intermediate revisions by one other user not shown) | |||
| Line 4: | Line 4: | ||
int main() | int main() | ||
{ | { | ||
int number | int number[10] = { 1,3,5,7,9,11,13,15,17,19 }; | ||
int *p; | int *p; | ||
| Line 18: | Line 18: | ||
int main() | int main() | ||
{ | { | ||
int number | int number[10] = { 1,3,5,7,9,11,13,15,17,19 }; | ||
int* p = &number | int* p = &number[0]; | ||
for (int i = 0; i < 10; i++) | for (int i = 0; i < 10; i++) | ||
{ | { | ||
printf("%d\n", p | printf("%d\n", p[i]); | ||
} | } | ||
return 0; | return 0; | ||
| Line 32: | Line 32: | ||
int main() | int main() | ||
{ | { | ||
int number | int number[10] = { 1,3,5,7,9,11,13,15,17,19 }; | ||
int* p = &number | int* p = &number[0]; | ||
for (int i = 0; i < 10; i++) | for (int i = 0; i < 10; i++) | ||
| Line 42: | Line 42: | ||
} | } | ||
== 2-1 == | == 2-1 == | ||
#include <stdio.h> | |||
int main() | |||
{ | |||
int number[3][4] = { {1,3,5,7},{9,11,13,15},{17,19,21,23} }; | |||
int * p; | |||
for (int i = 0; i < 3; i++) | |||
{ | |||
for(int j = 0; j < 4; j++) | |||
{ | |||
printf("%d\n", *(*(number + i)+ j)); | |||
} | |||
} | |||
return 0; | |||
} | |||
== 2-2 == | == 2-2 == | ||
#include <stdio.h> | |||
int main() | |||
{ | |||
int number[3][4] = { {1,3,5,7},{9,11,13,15},{17,19,21,23} }; | |||
int * p = &number[0][0]; | |||
for (int i = 0; i < 3; i++) | |||
{ | |||
for(int j = 0; j < 4; j++) | |||
{ | |||
printf("%d\n", *(p + i*4 + j)); | |||
} | |||
} | |||
return 0; | |||
} | |||
Latest revision as of 01:08, 27 March 2026
1-1
#include <stdio.h>
int main()
{
int number[10] = { 1,3,5,7,9,11,13,15,17,19 };
int *p;
for (int i = 0; i < 10; i++)
{
printf("%d\n", *(number+i));
}
return 0;
}
1-2
#include <stdio.h>
int main()
{
int number[10] = { 1,3,5,7,9,11,13,15,17,19 };
int* p = &number[0];
for (int i = 0; i < 10; i++)
{
printf("%d\n", p[i]);
}
return 0;
}
1-3
#include <stdio.h>
int main()
{
int number[10] = { 1,3,5,7,9,11,13,15,17,19 };
int* p = &number[0];
for (int i = 0; i < 10; i++)
{
printf("%d\n", *p++);
}
return 0;
}
2-1
#include <stdio.h>
int main()
{
int number[3][4] = { {1,3,5,7},{9,11,13,15},{17,19,21,23} };
int * p;
for (int i = 0; i < 3; i++)
{
for(int j = 0; j < 4; j++)
{
printf("%d\n", *(*(number + i)+ j));
}
}
return 0;
}
2-2
#include <stdio.h>
int main()
{
int number[3][4] = { {1,3,5,7},{9,11,13,15},{17,19,21,23} };
int * p = &number[0][0];
for (int i = 0; i < 3; i++)
{
for(int j = 0; j < 4; j++)
{
printf("%d\n", *(p + i*4 + j));
}
}
return 0;
}