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| * 2014년 4월 3일 개발
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| * 문제 : http://cau.ac.kr/~bongbong/c12/ -> Homework #4 -> Prob2. [[Bilinear Interpolation]]
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| #include <stdio.h>
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| #include <stdlib.h>
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|
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| #pragma warning(disable:4996)
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|
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| int computePosition(float, float);
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| float bilinearInterpolation(float*, float, float, int);
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|
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| int main()
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| {
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| float xValue, yValue, a, b;
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| float pointValue[25];
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| int i, position;
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|
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| printf("two float values x and y (ex: 0.5 1.0) : ");
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| scanf("%f %f",&xValue,&yValue);
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| printf("25 float values for the values at 25 grid points (ex: 1.0 3.5 ...)\n: ");
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| for(i = 0; i < 25; i++)
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| scanf("%f",&pointValue[i]);
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|
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| position = computePosition(xValue, yValue);
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| a = xValue - (int)xValue;
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| b = yValue - (int)yValue;
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|
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| printf("The Value at the coordinate (x,y) is %.3f\n",bilinearInterpolation(pointValue, a, b, position));
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| system("pause");
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| return 0;
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| }
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|
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| int computePosition(float xValue, float yValue)
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| {
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| int xposition = (int)xValue + 5*(int)yValue;
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| if(xposition%5 == 4)
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| xposition--;
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| if(xposition>=20)
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| xposition-=5;
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| return xposition;
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| }
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| float bilinearInterpolation(float pointValue[25],float a, float b, int position)
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| {
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| float f12, f34;
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| f12 = a*pointValue[position+1] + (1-a)*pointValue[position];
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| f34 = a*pointValue[position+6] + (1-a)*pointValue[position+5];
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| return b*f34 + (1-b)*f12;
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| }
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| -----
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| [[최다인]]
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